title: '算法:合并两个排序的链表' cover: https://img.paulzzh.com/touhou/random?25 categories: 算法题目 date: 1996-07-27 08:00:00 tags: [算法题目, 链表, 排序]
<br/>
<!--more-->输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则。
其实就是类似于归并排序中归并的操作;
public class Solution {
public ListNode Merge(ListNode list1, ListNode list2) {
if (list1 == null && list2 == null) return null;
if (list1 == null) return list2;
if (list2 == null) return list1;
ListNode scott = new ListNode(0);
ListNode cur = scott;
while (list1 != null && list2 != null) {
if (list1.val < list2.val) {
cur.next = list1;
list1 = list1.next;
} else {
cur.next = list2;
list2 = list2.next;
}
cur = cur.next;
}
if (list1 != null) cur.next = list1;
if (list2 != null) cur.next = list2;
return scott.next;
}
}