layout: "../layouts/BlogPost.astro" title: "String Matching – What’s behind Ctrl+F" slug: string-matching-whats-behind-ctrl-f description: "" added: "Mar 24 2024" tags: [other]
When we do search for a string in a notepad file, browser, or database, pattern searching algorithms are used to show the search results. Boyer-Moore String Search is one such pattern searching algorithm, meaning it has large area of practical use.
String matching - Search for a string (pattern) in a large body of text
Input:
Output:
The string-searching problem is to find all occurrences of pattern(s) in a text string. The Aho-Corasick string searching algorithm simultaneously finds all occurrences of multiple patterns in one pass through the text. On the other hand, the Boyer-Moore algorithm is understood to be the fastest algorithm for a single pattern.
procedure bruteForceSM(T, P)
for i = 0...n-m-1 do
for j = 0...m-1 do
if (T[i+j] != P[j]) then break inner loop
if j == m then return i
return NO_MATCH
Cost measure: #character comparisons
Worst possible input:
Let’s check from right to left (starting with the last character in the pattern). If we are lucky, we can eliminate several shifts in one shot.
New rules
<img alt="Bad character" src="https://raw.gitmirror.com/kexiZeroing/blog-images/main/bad-character.png" width="600">
<br> <img alt="Good suffix" src="https://raw.gitmirror.com/kexiZeroing/blog-images/main/good-suffix.png" width="600">
The preprocessing for the good suffix heuristics is rather difficult to understand and to implement. Therefore, sometimes versions of the Boyer-Moore algorithm are found in which the good suffix heuristics is left away.
// A simplified Boyer Moore implementation, using only the bad-character heuristic.
const ALPHABET_LEN = 256;
function ord(c) {
return c.charCodeAt(0);
}
// Bad character table: shift[c] contains the distance from the end of the
// pattern of the last occurrence of c for each character in the alphabet.
// If c does not occur in pat, shift[c] = pat.length
function bad_character_table(pat) {
let m = pat.length;
let shift = new Array(ALPHABET_LEN).fill(m);
for (let i = 0; i < m; i++) {
shift[ord(pat[i])] = m - i - 1;
}
return shift;
}
function simpleBoyerMoore(pattern, text) {
let i,
j,
matches = [],
m = pattern.length,
shift = bad_character_table(pattern);
i = m - 1;
while (i < text.length) {
j = m - 1;
while (j >= 0 && text[i] === pattern[j]) {
i -= 1;
j -= 1;
}
if (j < 0) {
matches.push(i + 1);
i += m + 1;
} else {
i += Math.max(m - j, shift[ord(text[i])]);
}
}
return matches;
}